Nathantiny2 OG combo guide: Difference between revisions
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== step 1: identifying opportunity == | == step 1: identifying opportunity == | ||
when chat is in an emote reactive setting, pay attention to how many letters the next chatter has in their name | when chat is in an emote reactive setting, pay attention to how many letters the next chatter has in their name | ||
Or be like eridu and pizza and just hit it because they are just so good! | Or be like eridu and pizza and just hit it because they are just so good! (this comment was made by eridu) | ||
== step 2: priming the combo == | == step 2: priming the combo == | ||
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[[File:perfectcombo.png|600px|left|a textbook example of a perfectly executed combo]] | [[File:perfectcombo.png|600px|left|a textbook example of a perfectly executed combo]] | ||
=== alternative "lazy" method === | |||
since text on dgg is not monospaced, counting can be unreliable and skipped entirely | |||
# type any emote in chat and send the message | |||
# immediately place your mouse cursor over the emote while your name is right above the input box | |||
# load a nathanTiny2_OG in the chamber and fire when an emote you wish to combo with appears under your cursor | |||
::::''adjust with underscores or other emotes as desired - this can be used to combo off yourself as well (is not nearly as cool typically)'' | |||
== step 3: brilliant success == | == step 3: brilliant success == | ||
if done properly, you will have | if done properly, you will have calculated or guessed the next chatter's name length and formed a uniquely glorious 2 line combo with another sentient chatter | ||
== step 4: bask in your victory == | == step 4: bask in your victory == | ||
everyone in chat loved the combo. even if you failed everyone loved it. they all appreciate your timing and humor | everyone in chat loved the combo. even if you failed everyone loved it. they all appreciate your timing and humor | ||
== step 5: calculate floating average meme stiffness == | == step 5: calculate floating average meme stiffness == | ||
take 'k' as the number of 'Klappa' emotes received | take 'k' as the number of 'Klappa' emotes received, | ||
take 'o' as the number of 'OhKrappa' emotes received | take 'o' as the number of 'OhKrappa' emotes received, | ||
assume <code>(k^2* k/1) / (o^2 * 1/o)</code> as your efficiency rate | |||
assume (k^2* k/1) / (o^2 * 1/o) as your efficiency rate | |||
Latest revision as of 02:18, 31 July 2023
step 1: identifying opportunity
when chat is in an emote reactive setting, pay attention to how many letters the next chatter has in their name
Or be like eridu and pizza and just hit it because they are just so good! (this comment was made by eridu)
step 2: priming the combo
from the table below, copy the string that correlates to the next chatters name length and paste it into chat quickly
| underscore spacing | string | chance of success |
| 1 | __ nathanTiny2_OG | 25% |
| 2 | _______ nathanTiny2_OG | 60% |
| 3 | __________ nathanTiny2_OG | 50% |
| 4 | _____________ nathanTiny2_OG | 38% |
| 5 | ___________________ nathanTiny2_OG | 32% |
alternative "lazy" method
since text on dgg is not monospaced, counting can be unreliable and skipped entirely
- type any emote in chat and send the message
- immediately place your mouse cursor over the emote while your name is right above the input box
- load a nathanTiny2_OG in the chamber and fire when an emote you wish to combo with appears under your cursor
- adjust with underscores or other emotes as desired - this can be used to combo off yourself as well (is not nearly as cool typically)
step 3: brilliant success
if done properly, you will have calculated or guessed the next chatter's name length and formed a uniquely glorious 2 line combo with another sentient chatter
step 4: bask in your victory
everyone in chat loved the combo. even if you failed everyone loved it. they all appreciate your timing and humor
step 5: calculate floating average meme stiffness
take 'k' as the number of 'Klappa' emotes received,
take 'o' as the number of 'OhKrappa' emotes received,
assume (k^2* k/1) / (o^2 * 1/o) as your efficiency rate